Extracting Digits from Float numbers

A friend just came up with an unusual request for me, to "intelligently" extract each digit from a float number.
He wanted each digit from the number sent by the Micro controller to be extracted separately to display on his Display Unit... While type-casting will lead to total loss of precision, and mathematical operations are useless if you think of any.

So I decided to convert this number entirely to a string, complete with the "dot" decimal and then refer to them as an array of characters. Please note that there is a loss involved due to size of the array but that is minimal.
The limit of numbers that will be displayed is 6, excluding the decimal number.

I, luckily found a library function to do the task....its called sprintf and declared inside stdio.h. Code looks like this.

/***************************************************************/
#include <iostream.h>
#include <conio.h>
#include <stdio.h>
#define nmbr 48.88         //Float number to be processed
void main()
{
clrscr();
char num[6];               //Recipient array
sprintf(num,"%f",nmbr);    /*Function requires Recipient        
                                   array, Datatype float, and our  
                                   float number 48.8*/
cout<<"\nDECIMAL PART:\n";

for(int i=0;i<6;i++)       //Simple array traversing
{
if(num[i]=='.')
{
cout<<"\nFRACTIONAL PART:\n";
continue;
}
cout<< num[i];                  /* Instead of displaying, the    
                                  character can be processed to   
                                  obtain any desired result*/
}
getch();
}
/***************************************************************/

OUTPUT